हिंदी

A ray of light passes through an equilateral prism such that the angle of incidence is equal to the angle of emergence and each of these is equal to 3/4 of the angle of the prism.

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प्रश्न

A ray of light passes through an equilateral prism such that the angle of incidence is equal to the angle of emergence and each of these is equal to `3/4` of the angle of the prism. The angle of deviation is:

विकल्प

  • 45°

  • 29°

  • 30°

  • 20°

MCQ
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उत्तर

30°

Explanation:

Given Data:

The angle of the prism (A) = 60°

Angle of incidence (i) = Angle of emergence (e)

Each angle is equal to `3/4` of the angle of the prism (A).

Calculation:

i = e = `3/4 xx A`

= `3/4 xx 60°`

= 45°

Use the standard prism formula relating the angles:

A + δ = i + e

60° + δ + 45° + 45°

60° + δ = 90°

δ = 90° − 60°

δ = 30°

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अध्याय 4: Refraction of Light at Plane Surfaces - Intex Question [पृष्ठ ८७]

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लखमीर सिंग Physics [English] Class 10 ICSE
अध्याय 4 Refraction of Light at Plane Surfaces
Intex Question | Q 4. (i) | पृष्ठ ८७
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