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प्रश्न
A ray of light passes through an equilateral prism such that the angle of incidence is equal to the angle of emergence and each of these is equal to `3/4` of the angle of the prism. The angle of deviation is:
विकल्प
45°
29°
30°
20°
MCQ
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उत्तर
30°
Explanation:
Given Data:
The angle of the prism (A) = 60°
Angle of incidence (i) = Angle of emergence (e)
Each angle is equal to `3/4` of the angle of the prism (A).
Calculation:
i = e = `3/4 xx A`
= `3/4 xx 60°`
= 45°
Use the standard prism formula relating the angles:
A + δ = i + e
60° + δ + 45° + 45°
60° + δ = 90°
δ = 90° − 60°
δ = 30°
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