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प्रश्न
A quadrilateral ABCD is drawn to circumscribe a circle, as shown in the given figure. Show that `(AB + CD)/(AD + BC)` = 1.
योग
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उत्तर
Tangents drawn to a circle from an external point are equal.
So, AP = AS,
PB = BQ,
CR = CQ,
DR = DS
On adding the above equations,
(AP + PB) + (CR + RD) = (AS + BQ) + (CQ + DS)
⇒ AB + CD = AD + BC
⇒ `(AB + CD)/(AD + BC)` = 1
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