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प्रश्न
A person standing between two vertical cliffs and 480 m from the nearest cliff shouts. He hears the first echo after 3s and the second echo 2s later. Calculate:
- The speed of sound.
- The distance of the other cliff from the person
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उत्तर
Given: Distance of nearest cliff, \(d_1 = 480\ \text{m}\)
Time for first echo, \(t_1 = 3\ \text{s}\)
(i) For an echo, sound travels to the cliff and back:
\[ v=\frac{2d_1}{t_1} \]
\[ v=\frac{2\times480}{3}\]
\[ {v=320\ \text{m/s}} \]
(ii) The second echo is heard 2 s after the first echo.
\[ t_2=3+2=5\ \text{s} \]
Let the distance of the other cliff be \(d_2\).
\[ d_2=\frac{vt_2}{2} \]
\[ d_2=\frac{320\times5}{2}\]
\[{d_2=800\ \text{m}} \]
संबंधित प्रश्न
Name the factor that determines Loudness of the sound heard.
State two conditions for an echo to take place.
Name one property of waves that do not change when the wave passes from one medium to another.
The distance from one compression to nearest rarefaction is called wavelength.
A man playing a flute is able to produce notes of different frequencies. If he closes the holes near his mouth, will the pitch of the note produced, increase or decrease? Give a reason.
The same musical note when played on a piano and when played on a flute sounds different.
Give scientific reason.
In earlier times, people used to listen for the arrival of a distant train by putting their ear to the rail.
