Question

A parallel plate capacitor is maintained at potential of 400 V. If area of plates is 40 cm² and separation between plates is 40 mm, calculate displacement current in 1μs.

Answer 1

Given: V = 400 V

A = 40 cm²

= 40 × 10⁻⁴ m²

d = 40 mm

= 40 × 10⁻³ m

dt = 1 × 10⁻⁶ s

To find: I_d = ?

Formula: E = `v/d`

= `400/(40 xx 10^-3)`

= 10⁴ V/m

`I_d = Aε_0 (dE)/(dt)`

= `40 xx 10^-4 xx 8.85 xx 10^-12 xx (10^4)/(10^-6)`

= 3.54 × 10⁻⁴ A