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A long solenoid is fabricated by closely winding a wire of radius 0.5 mm over a cylindrical nonmagnetic frame so that the successive turns nearly touch each other.

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प्रश्न

A long solenoid is fabricated by closely winding a wire of radius 0.5 mm over a cylindrical nonmagnetic frame so that the successive turns nearly touch each other. What would be the magnetic field B at the centre of the solenoid if it carries a current of 5 A? 

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उत्तर

Given:
Radius of the wire, r = 0.5 mm
Width of each turn, = diameter of the wire, 2r = 1 mm = 1 × 10−3 m
∴ Total number of turns in 1 m solenoid 

`n = 1/(1 xx 10^-3 ) = 10^3`

Magnitute of current , i = 5 A

Using B = `mu _0 ni , ` We get 

`B  = 4 pi xx 10^-7 xx 10^3 xx 5`

`B = 2 pi xx 10^-3` T

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अध्याय 35: Magnetic Field due to a Current - Exercises [पृष्ठ २५२]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 35 Magnetic Field due to a Current
Exercises | Q 55 | पृष्ठ २५२

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