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A ladder 17 metre long is leaning against the wall. The base of the ladder is pulled away from the wall at a rate of 5 m/s. When the base of the ladder is 8 metres from the wall. How - Mathematics

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प्रश्न

A ladder 17 metre long is leaning against the wall. The base of the ladder is pulled away from the wall at a rate of 5 m/s. When the base of the ladder is 8 metres from the wall. How fast is the top of the ladder moving down the wall?

योग
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उत्तर

Let the height of the wall where the ladder touches are ‘y’ m.

The bottom of the ladder is at a distance of ‘x’ m from the wall.

Given x = 8, `("d"x)/"dt"` = 5

x2 + y2 = 172

Pythagoras Theorem

y2 = 172 – x2

= 289 – 64

= 225

∴ y = 15

Differentiating w.r.t. ‘t’

`2x ("d"x)/"dt" + 2y ("d"y)/"dt"` = 0  .....(÷ 2)

`x ("d"x)/"dt" + y ("d"y)/"dt"` = 0

`8(5) + 15 ("d"y)/"dt"` = 0

∴ `("d"y)/"dt" =  40/15`

= `- 8/5`

The top of the ladder is moving down the wall at the rate of `8/3` m/sec

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Applications of Differential Calculus - Exercise 7.1 [पृष्ठ ८]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 7 Applications of Differential Calculus
Exercise 7.1 | Q 9. (i) | पृष्ठ ८

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