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प्रश्न
A heavy nucleus X of mass number 240 and binding energy per nucleon 7.6 MeV is split into two fragments Y and Z of mass numbers 110 and 130. The binding energy of nucleons in Y and Z is 8.5 MeV per nucleon. Calculate the energy Q released per fission in MeV.
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उत्तर
Total energy of nucleus X = 240 × 7.6 = 1824 MeV
Total energy of nucleus Y = 110 × 8.5 = 935 MeV
Total energy of nucleus Z = 130 × 8.5 = 1105 MeV
Therefore, energy released from fission, Q = 935 + 1105 − 1824 = 216 MeV
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संबंधित प्रश्न
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