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A five digit number divisible by 3 is to be formed using the numbers 0, 1, 2, 3, 4 and 5 without repetitions. The total number of ways this can be done is ______. - Mathematics

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प्रश्न

A five-digit number divisible by 3 is to be formed using the numbers 0, 1, 2, 3, 4 and 5 without repetitions. The total number of ways this can be done is ______.

विकल्प

  • 216

  • 600

  • 240

  • 3125

MCQ
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उत्तर

A five-digit number divisible by 3 is to be formed using the numbers 0, 1, 2, 3, 4 and 5 without repetitions. The total number of ways this can be done is 216.

Explanation:

We know that a number is divisible by 3 when the sum of its digits is divisible by 3.

If we take the digits 0, 1, 2, 4, 5, then the sum of the digits

= 0 + 1 + 2 + 4 + 5 = 12 which is divisible by 3

So, the 5 digit numbers using the digits 0, 1, 2, 4, and 5

TTh  Th  H   T  O
  4     4   3   2   1

= 4 × 4 × 3 × 2 × 1

= 96

And if we take the digits 1, 2, 3, 4, 5, then their sum

= 1 + 2 + 3 + 4 + 5

= 15 divisible by 3

So, five-digit numbers can be formed using the digits 1, 2, 3, 4, 5 is 5! ways

= 5 × 4 × 3 × 2 × 1

= 120 ways

Total number of ways = 96 + 120

= 216.

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अध्याय 7: Permutations and Combinations - Exercise [पृष्ठ १२४]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 7 Permutations and Combinations
Exercise | Q 31 | पृष्ठ १२४

वीडियो ट्यूटोरियलVIEW ALL [1]

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