Advertisements
Advertisements
प्रश्न
A field is in the shape of a trapezium whose parallel sides are 25 m and 10 m. The non-parallel sides are 14 m and 13 m. Find the area of the field.
Advertisements
उत्तर

Draw a line BE parallel to AD and draw a perpendicular BF on CD.
It can be observed that ABED is a parallelogram.
BE = AD = 13 m
ED = AB = 10 m
EC = 25 − ED = 15 m
For ΔBEC,
Semi-perimeter,
`s=(13+14+15)/2=21 m`
By Heron’s formula,
`"Area of triangle "=sqrt(s(s-a)(s-b)(s-c))`
`"Area of ΔBEC "=[sqrt(21(21-13)(21-14)(21-15))]m^2`
`=[sqrt(21(8)(7)(6))]m^2`
= 84 m2
`"Area of ΔBEC "=1/2xxCExxBF`
`rArr84=1/2xx15xxBF`
`rArrBF=168/15=11.2 m`
Area of ABED = BF × DE = 11.2 × 10 = 112 m2
Area of the field = 84 + 112 = 196 m2
संबंधित प्रश्न
A park, in the shape of a quadrilateral ABCD, has ∠C = 90°, AB = 9 m, BC = 12 m, CD = 5 m and AD = 8 m. How much area does it occupy?
Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.
The sides of a quadrilateral, taken in order are 5, 12, 14 and 15 meters respectively, and the angle contained by the first two sides is a right angle. Find its are
Find the area of an equilateral triangle having each side 4 cm.
The sides of a triangle are 50 cm, 78 cm and 112 cm. The smallest altitude is
The sides of a triangle are 11 m, 60 m and 61 m. The altitude to the smallest side is
The base and hypotenuse of a right triangle are respectively 5 cm and 13 cm long. Its area is ______.
A park is in the shape of a quadrilateral. The sides of the park are 15 m, 20 m, 26 m and 17 m and the angle between the first two sides is a right angle. Find the area of the park
The adjacent sides of a parallelogram measures 34 m, 20 m and the measure of the diagonal is 42 m. Find the area of parallelogram
The area of an isosceles triangle having base 2 cm and the length of one of the equal sides 4 cm, is ______.
