Advertisements
Advertisements
प्रश्न
A circular field of radius 105 m has a circular path of uniform width of 5 m along and inside its boundary. Find the area of the path.
Advertisements
उत्तर
The radius of circular field, `r_1 = 105`m
Width of path = 50 m
∴ The radius of the inner circle, `r_2 = 105 - 5 = 100`m
Area of path = `pir_1^2 - pir_2^2`
= `22/7[(105)^2 - (100)^2]`
= `22/7(105 + 100)(105 - 100)`
= `22/7 xx 205 xx 5`
= `22550/7`m2
= `3221 3/7`m2
APPEARS IN
संबंधित प्रश्न
The length and breadth of a rectangular garden are in the ratio 9:5. A path 3.5 m wide, running all around inside it has an area of `1911m^2` . Find the dimensions of the garden.
From a thin metallic piece, in the shape of a trapezium ABCD, in which AB || CD and ∠BCD = 90°, a quarter circle BEFC is removed (in the following figure). Given AB = BC = 3.5 cm and DE = 2 cm, calculate the area of the remaining piece of the metal sheet.
Find the area of the largest triangle that can be inscribed in a semi-circle of radius runits.
The area of incircle of an equilateral triangle is 154 cm2 . The perimeter of the triangle is
ABCD is a rectangle whose three vertices are B (4,0), C (4,3) and D (0, 3). The length of one of its diagonals is
Four equal circles, each of radius 5 cm, touch each other, as shown in the figure. Find the area included between them.
A racetrack is in the form of a ring whose inner circumference is 352 m and outer circumference is 396 m. Find the width and the area of the track.
Find the area of a flat circular ring formed by two concentric circles (circles with the same centre) whose radii are 9 cm and 5 cm.
Diameter of a circular garden is 9.8 m. Find its area.
Thenmozhi wants to level her circular flower garden whose diameter is 49 m at the rate of ₹ 150 per m2 Find the cost of levelling
