Advertisements
Advertisements
प्रश्न
There is a path of uniform width 7 m round and outside a circular garden of diameter 210 m. Find the area of the path.
Advertisements
उत्तर
Diameter = 210 m
Radius of inner circle r2 = 105 m
Width = 7m
Radius of outer circle r1 = 105 + 7 = 112 m
∴ Area of path = `pir_1^2 - pir_2^2`
= `pi[r_1^2 - r_2^2]`
= `22/7(r_1 + r_2)(r_1 + r_2)`
= `22/7 (112 + 105)(112 - 105)`
= `22/7 xx 217 xx 7`
= 4774 m2
APPEARS IN
संबंधित प्रश्न
The area of a square filed is 8 hectares. How long would a man take to cross it diagonally by walking at the rate of 4 km per hour?
The cost of fencing a square lawn at ₹ 14 per meter is ₹ 28000. Find the cost of mowing the lawn at ₹ 54 100 per `m^2`
In the given figure ABCD is quadrilateral in which diagonal BD = 24 cm, AL ⊥ BD and CM ⊥ BD such that AL = 9cm and CM = 12 cm. Calculate the area of the quadrilateral.
A path of width 3.5 m runs around a semi-circular grassy plot whose perimeter is 72 m . Find the area of the path .
`("Use" pi= 22/7) `
If three circles of radius a each, are drawn such that each touches the other two, prove that the area included between them is equal to `4/25"a"^2`.
The length of the minute hand of a clock is 21 cm. The area swept by the minute hand in 10 minutes is
If a square in inscribed in a circle, find the ratio of the areas of the circle and the square.
Diameter of a circular garden is 9.8 m. Find its area.
The area of the circle that can be inscribed in a square of side 6 cm is ______.
A table top is semicircular in shape with diameter 2.8 m. Area of this table top is ______.
