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प्रश्न
A circular cycle track has a circumstance of 314 m with AB as one of its diameter. A cyclist travels from A to B along the circular path with a velocity of constant magnitude 15. 7 m/ s. Find :
(a) The distance moved by the cyclist.
(b) The displacement of the cyclist if AB represents north-south direction .
(c) The average velocity of the cyclist.
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उत्तर
Circumference of track = 314 m.
We know that circumference = 2nr
So 2nr = 314
R = 314/ 2n = 50 m
Diameter of track would be = 2 x 50 = 100 m.
Length of path AB= 100 m.
(a) Distance moved by cyclist= half the circumference of track i.e 314/ 2 = 157 m.
(b) The displacement of cyclist is equal to the diameter of circle i.e AB= 100 m.
(c) Average velocity would be equal to = 15.7 ms-1.
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