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प्रश्न
A certain salt X, gives the following results.
- Its aqueous solution is alkaline to litmus.
- It swells up to a glassy material Y on strong heating.
- When conc. H2SO4 is added to a hot solution of X, white crystal of an acid Z separates out.
Write equations for all the above reactions and identify X, Y and Z.
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उत्तर
The given salt is alkaline to litmus. Therefore, X is a salt of a strong base and a weak acid. Also, when X is strongly heated, it swells to form substance Y. Therefore, X must be borax.
When borax is heated, it loses water and swells to form sodium metaborate. When heating is continued, it solidifies to form a glassy material Y. Hence, Y must be a mixture of sodium metaborate and boric anhydride.
\[\ce{\underset{Borax (X)}{Na2B4O7} + 7H2O ->[water] \underset{Sodium hydroxide}{2NaOH} + \underset{Orthoboric acid}{4H3BO3}}\]
\[\ce{\underset{Borax (X)}{Na2B4O7 * 10H2O} ->[\Delta] \underset{Sodium metaborate}{Na2B4O7} ->[\Delta] \underset{(Glassy material)}{\underset{Boric anhydric}{B2O3}} + 2NaBO2}\]
When concentrated acid is added to borax, white crystals of orthoboric acid (Z) are formed.
\[\ce{\underset{Borax (X)}{Na2B4O7 * 10H2O} + H2SO4 ->[\Delta] Na2SO4 +\underset{Orthoboric acid}{4H3BO3 + 5H2O}}\]
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