Advertisements
Advertisements
प्रश्न
A body of mass 60 kg has the momentum 3000 kg m s-1. Calculate:
- the kinetic energy.
- the speed of the body.
Advertisements
उत्तर
(i) Kinetic Energy K.E. = `1/2 mv^2`
= `1/2 xx 60 xx 50 xx 50`
= 75000 J
= `75/10 xx 10000 J`
= 7.5 × 104 J
(ii) Mass of body m = 60 kg
momentum p = mv
= 3000 kg ms-1
∴ 60 V = 3000
∴ V = `3000/60`
= 50 ms-1
APPEARS IN
संबंधित प्रश्न
An object of mass 40 kg is raised to a height of 5 m above the ground. What is its potential energy? If the object is allowed to fall, find its kinetic energy when it is half-way down.
An object of mass, m is moving with a constant velocity, v. How much work should be done on the object in order to bring the object to rest?
Certain force acting on a 20 kg mass changes its velocity from 5 m s-1 to 2 m s-1. Calculate the work done by the force.
Define the term kinetic energy. Give one example of a body which possesses kinetic energy.
State two factors on which the kinetic energy of a moving body depends.
Two bodies have masses in the ratio 5 : 1 and their kinetic energies are in the ratio 125 : 9. Calculate the ratio of their velocities.
On a level road, a scooterist applies brakes to slow down from a speed of 10 m/s to 5 m/s. If the mass of the scooterist and the scooter be 150 kg, calculate the work done by the brakes. (Neglect air resistance and friction)
Derive the formula for the kinetic energy of an object of mass m, moving with velocity v.
When a bell fixed on a cycle rings, then the energy conversion that takes place is ______.
If the mass as well as the velocity of a body is doubled then the kinetic energy of the body ______ the initial kinetic energy.
