Advertisements
Advertisements
प्रश्न
A body of mass 60 kg has the momentum 3000 kg m s-1. Calculate:
- the kinetic energy.
- the speed of the body.
Advertisements
उत्तर
(i) Kinetic Energy K.E. = `1/2 mv^2`
= `1/2 xx 60 xx 50 xx 50`
= 75000 J
= `75/10 xx 10000 J`
= 7.5 × 104 J
(ii) Mass of body m = 60 kg
momentum p = mv
= 3000 kg ms-1
∴ 60 V = 3000
∴ V = `3000/60`
= 50 ms-1
APPEARS IN
संबंधित प्रश्न
An object of mass, m is moving with a constant velocity, v. How much work should be done on the object in order to bring the object to rest?
Name the unit of physical quantity obtained by the formula `(2K)/v^2` Where K: kinetic energy, v: linear velocity
Kinetic energy = 1/2 × mass × ............
When a boy doubles his speed, his kinetic energy becomes
When an arrow is shot from a bow, it has kinetic energy in it. Explain briefly from where does it get its kinetic energy?
A ball of mass 200 g falls from a height of 5 metres. What is its kinetic energy when it just reaches the ground? (g = 9.8 m/s2)
What do you understand by the kinetic energy of a body?
When a ball is thrown inside a moving bus, does its kinetic energy depend on the speed of the bus? Explain.
When stored water falls down, potential energy of water is converted into ______.
The kinetic energy of a body of mass 4 kg and momentum 6 Ns will be
