Advertisements
Advertisements
प्रश्न
Two bodies of equal masses are moving with uniform velocities v and 2v. Find the ratio of their kinetic energies.
Advertisements
उत्तर
K.E = `1/2 mv^2`
K.E = `1/2 m (2v)^2`
K.E = `(1/2 mv^2) xx 4`
∴ Ratio of their K.E = `(1/2 mv^2)/(4(1/2 mv^2))`
= `1/4`
= 1 : 4
Ratio of K.E. of A and B is 1 : 4.
APPEARS IN
संबंधित प्रश्न
Name the unit of physical quantity obtained by the formula `(2K)/v^2` Where K: kinetic energy, v: linear velocity
Define the term kinetic energy. Give one example of a body which possesses kinetic energy.
A car is moving with a speed of 15 km h-1 and another identical car is moving with a speed of 30 km h-1. Compare their kinetic energy.
When an arrow is shot from a bow, it has kinetic energy in it. Explain briefly from where does it get its kinetic energy?
A body falls freely under gravity from rest. Name the kind of energy it will possess on reaching the ground.
Two bodies have masses in the ratio 5 : 1 and their kinetic energies are in the ratio 125 : 9. Calculate the ratio of their velocities.
On what factors does the kinetic energy of a body depend?
What is the kinetic energy of a body of mass 1 kg moving with a speed of 2 m/s?
A ball of mass 200 g falls from a height of 5 metres. What is its kinetic energy when it just reaches the ground? (g = 9.8 m/s2)
The kinetic energy of a body of mass 4 kg and momentum 6 Ns will be
