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प्रश्न
A block of iron of mass 7.5 kg and of dimensions 12 cm × 8 cm × 10 cm is kept on a table top on its base of side 12 cm × 8 cm.
Calculate:
- Thrust and
- Pressure exerted on the table top
Take 1 kgf = 10 N.
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उत्तर
1 kgf = 10 N
∴ g = 10 ms-2
1) Thrust is
F = mg
= 7.5 kg × 10
= 75 N
2) Pressure is force per area.
∴ P = `"F"/"A"_"base"`
= `75/(12 xx 10^-2 xx 8 xx 10^-2)`
∴ P = 7812.5 Pa
संबंधित प्रश्न
What is the other name of buoyant force ?
What is meant by the term ‘buoyancy’ ?
The density of water is 1.0 g Cm-3. The density of iron is 7.8 × 10″3 g Cm-3. The density of mercury is 13.6 g Cm-3.
Answer the following:
Will a piece of iron float or sink in mercury?
State the laws of liquid pressure.
Complete the following sentence :
Pressure at a point inside the liquid is ...................... To its depth.
Complete the following sentence.
Mass = .................... × density
What is meant by up thrust?
How is thrust different from pressure?
Assertion (A): The buoyant force on a submerged rigid object can be considered to be acting at the center of mass of the object.
Reason (R): In rigid body, force distributed uniformly through its volume can be considered to be acting at the centre of mass of the body.
Complete the analogy.
Downward force : Weight :: Upward force offered by liquid : ______
