हिंदी

A ∫ 0 3 X 2 D X = 8 , Find the Value of A.

Advertisements
Advertisements

प्रश्न

\[\int\limits_0^a 3 x^2 dx = 8,\] find the value of a.

Advertisements

उत्तर

\[\text{We have}, \]
\[ \int_0^a 3 x^2 d x = 8\]
\[ \Rightarrow \left[ 3 \frac{x^3}{3} \right]_0^a = 8\]
\[ \Rightarrow a^3 = 8\]
\[ \Rightarrow a = 2\]

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 19: Definite Integrals - Exercise 20.1 [पृष्ठ १८]

APPEARS IN

आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 19 Definite Integrals
Exercise 20.1 | Q 61 | पृष्ठ १८

संबंधित प्रश्न

Prove that: `int_0^(2a)f(x)dx=int_0^af(x)dx+int_0^af(2a-x)dx`


If `int_0^alpha3x^2dx=8` then the value of α is :

(a) 0

(b) -2

(c) 2 

(d) ±2


By using the properties of the definite integral, evaluate the integral:

`int_0^(pi/2) cos^2 x dx`


By using the properties of the definite integral, evaluate the integral:

`int_2^8 |x - 5| dx`


By using the properties of the definite integral, evaluate the integral:

`int_((-pi)/2)^(pi/2) sin^2 x  dx`


By using the properties of the definite integral, evaluate the integral:

`int_0^pi (x  dx)/(1+ sin x)`


`∫_4^9 1/sqrtxdx=`_____

(A) 1

(B) –2

(C) 2

(D) –1


Evaluate : \[\int(3x - 2) \sqrt{x^2 + x + 1}dx\] .


Evaluate  : `int "x"^2/("x"^4 + 5"x"^2 + 6) "dx"`


Prove that `int_0^"a" "f" ("x") "dx" = int_0^"a" "f" ("a" - "x") "d x",` hence evaluate `int_0^pi ("x" sin "x")/(1 + cos^2 "x") "dx"`


Evaluate `int_1^3 x^2*log x  "d"x`


`int (cos x + x sin x)/(x(x + cos x))`dx = ?


`int_0^(pi/4) (sec^2 x)/((1 + tan x)(2 + tan x))`dx = ?


`int_0^4 1/(1 + sqrtx)`dx = ______.


`int_"a"^"b" sqrtx/(sqrtx + sqrt("a" + "b" - x)) "dx"` = ______.


`int_0^(pi/2) sqrt(cos theta) * sin^2 theta "d" theta` = ______.


`int_0^{pi/4} (sin2x)/(sin^4x + cos^4x)dx` = ____________


`int_(pi/18)^((4pi)/9) (2 sqrt(sin x))/(sqrt (sin x) + sqrt(cos x))` dx = ?


`int_0^pi x*sin x*cos^4x  "d"x` = ______.


`int_0^1 "e"^(5logx) "d"x` = ______.


Evaluate: `int_(pi/6)^(pi/3) (dx)/(1 + sqrt(tanx)`


Evaluate: `int_1^3 sqrt(x)/(sqrt(x) + sqrt(4) - x) dx`


Evaluate: `int_2^5 sqrt(x)/(sqrt(x) + sqrt(7) - x)dx`


`int_a^b f(x)dx = int_a^b f(x - a - b)dx`.


If `intxf(x)dx = (f(x))/2` then f(x) = ex.


Let f be a real valued continuous function on [0, 1] and f(x) = `x + int_0^1 (x - t)f(t)dt`. Then, which of the following points (x, y) lies on the curve y = f(x)?


If `int_(-a)^a(|x| + |x - 2|)dx` = 22, (a > 2) and [x] denotes the greatest integer ≤ x, then `int_a^(-a)(x + [x])dx` is equal to ______.


Evaluate `int_0^(π//4) log (1 + tanx)dx`.


Evaluate `int_-1^1 |x^4 - x|dx`.


If `int_0^(2π) cos^2 x  dx = k int_0^(π/2) cos^2 x  dx`, then the value of k is ______.


Evaluate `int_0^3root3(x+4)/(root3(x+4)+root3(7-x))  dx`


Solve the following.

`int_0^1e^(x^2)x^3 dx`


Evaluate the following integrals:

`int_-9^9 x^3/(4 - x^3 ) dx`


Evaluate the following integral:

`int_-9^9 x^3/(4-x^2)dx`


Evaluate the following integral:

`int_-9^9x^3/(4-x^2)dx`


Evaluate the following integral:

`int_-9^9x^3/(4-x^2)dx`


Under which condition does \[P_6\] give \[\int_{0}^{2a} f(x)\,dx=2\int_{0}^{a} f(x)\,dx\]?


Why can \[\int_{-\frac{\pi}{4}}^{\frac{\pi}{4}}\sin^{2}x\,dx\] be written as \[2\int_{0}^{\frac{\pi}{4}}\sin^{2}x\,dx\]?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×