Question

`2x^2+5x-3=0`

Answer 1

`2x^2+5x-3=0` 

⇒`4x^2+10x-6=0`                              (Multiplying both sides by 2)

4x^+10x=6 

`(2x)^2+2xx2x xx5/2+(5/2)^2=6+(5/2)^2` [Adding `(5/2)^2`on both sides] 

`(2x+5/2)^2=6+25/4=(24+25)/4=49/4=(7/2)^2` 

`2x+5/2=7/2`                   (Taking square root on both sides) 

`2x+5/2=7/2  or  2x+5/2=7/2` 

`2x=7/2-5/2=2/3=1  or  2x=-7/2-5/2=12/2=-6` 

`x=1/2  or  x=-3` 

Hence, `1/2` and `-3`are the roots of the given equation.