Advertisements
Advertisements
प्रश्न
12, 16, 20, 24,...... Find 25th term of this A.P.
Advertisements
उत्तर
The given A.P. is 12, 16, 20, 24,......
Here, a = 12, d = 16 – 12 = 4
Since tn = a + (n – 1)d
t25 = 12 + (25 – 1)(4)
= 12 + 24(4)
= 12 + 96
= 108
∴ 25th term of the given A.P. is 108.
APPEARS IN
संबंधित प्रश्न
If the 9th term of an A.P. is zero, then prove that 29th term is double of 19th term.
Find the sum of the following arithmetic series:
`7 + 10 1/2 + 14 + ... + 84`
Find the sum of the following arithmetic series:
34 + 32 + 30 + ... + 10
Decide whether the following sequence is an A.P., if so find the 20th term of the progression:
–12, –5, 2, 9, 16, 23, 30, ..............
Given Arithmetic Progression 12, 16, 20, 24, . . . Find the 24th term of this progression.
Six year before, the age of mother was equal to the square of her son's age. Three year hence, her age will be thrice the age of her son then. Find the present ages of the mother and son.
Select the correct alternative and write it.
What is the sum of first n natural numbers ?
Select the correct alternative and write it.
If a share is at premium, then -
Find the 23rd term of the following A.P.: 9, 4,-1,-6,-11.
Find tn if a = 20 and d = 3.
Decide whether the given sequence 24, 17, 10, 3,...... is an A.P.? If yes find its common term (tn).
How many two-digit numbers are divisible by 5?
Activity :- Two-digit numbers divisible by 5 are, 10, 15, 20, ......, 95.
Here, d = 5, therefore this sequence is an A.P.
Here, a = 10, d = 5, tn = 95, n = ?
tn = a + (n – 1) `square`
`square` = 10 + (n – 1) × 5
`square` = (n – 1) × 5
`square` = (n – 1)
Therefore n = `square`
There are `square` two-digit numbers divisible by 5.
The nth term of an A.P. 5, 8, 11, 14,...... is 68. Find n = ?
If p - 1, p + 3, 3p - 1 are in AP, then p is equal to ______.
Find a and b so that the numbers a, 7, b, 23 are in A.P.
Write the next two terms of the A.P.: `sqrt(27), sqrt(48), sqrt(75)`......
