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`(1+ Cos Theta - Sin^2 Theta )/(Sin Theta (1+ Cos Theta))= Cot Theta` - Mathematics

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`(1+ cos  theta - sin^2 theta )/(sin theta (1+ cos theta))= cot theta`

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LHS= `(1+ cos  theta - sin^2 theta )/(sin theta (1+ cos theta)`

     =` ((1+ cos theta )- (1-cos^2 theta))/(sin theta(1+ cos theta))`

     =`(cos theta + cos^2 theta)/( sin theta ( 1+ cos theta))`

     =`(cos theta ( 1+ cos theta ))/ ( sin theta ( 1+ cos theta))`

     =`cos theta/ sin theta`

     = cot ЁЭЬГ
     = RHS
Hence, L.H.S. = R.H.S.

  

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рдЕрдзреНрдпрд╛рдп 8: Trigonometric Identities - Exercises 1

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рдЖрд░.рдПрд╕. рдЕрдЧреНрд░рд╡рд╛рд▓ Mathematics [English] Class 10
рдЕрдзреНрдпрд╛рдп 8 Trigonometric Identities
Exercises 1 | Q 25

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Prove the following trigonometric identities.

`(1 - sin theta)/(1 + sin theta) = (sec theta - tan theta)^2`


Prove the following trigonometric identities.

`tan^2 theta - sin^2 theta tan^2 theta sin^2 theta`


Prove the following identities:

`(1 + sinA)/cosA + cosA/(1 + sinA) = 2secA`


Prove that:

`tanA/(1 - cotA) + cotA/(1 - tanA) = secA  "cosec"  A + 1`


If x cos A + y sin A = m and x sin A – y cos A = n, then prove that : x2 + y2 = m2 + n2


If 4 cos2 A – 3 = 0, show that: cos 3 A = 4 cos3 A – 3 cos A


`cos^2 theta /((1 tan theta))+ sin ^3 theta/((sin theta - cos theta))=(1+sin theta cos theta)`


Write the value of `( 1- sin ^2 theta  ) sec^2 theta.`


Write the value of tan1° tan 2°   ........ tan 89° .


If \[sec\theta + tan\theta = x\] then \[tan\theta =\] 


The value of sin2 29° + sin2 61° is


Prove the following identity :

cosecθ(1 + cosθ)(cosecθ - cotθ) = 1


Prove the following identities:

`(tan"A"+tan"B")/(cot"A"+cot"B")=tan"A"tan"B"`


Prove that: (1+cot A - cosecA)(1 + tan A+ secA) =2. 


Prove that `(sin 70°)/(cos 20°) + (cosec 20°)/(sec 70°) - 2 cos 70° xx cosec 20°` = 0.


Prove that: `(sin A + cos A)/(sin A - cos A) + (sin A - cos A)/(sin A + cos A) = 2/(sin^2 A - cos^2 A)`.


Prove the following identities.

cot θ + tan θ = sec θ cosec θ


sin2θ + sin2(90 – θ) = ?


The value of 2sinθ can be `a + 1/a`, where a is a positive number, and a ≠ 1.


`1/sin^2θ - 1/cos^2θ - 1/tan^2θ - 1/cot^2θ - 1/sec^2θ - 1/("cosec"^2θ) = -3`, then find the value of θ.


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