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`(1+ Cos Theta - Sin^2 Theta )/(Sin Theta (1+ Cos Theta))= Cot Theta` - Mathematics

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`(1+ cos  theta - sin^2 theta )/(sin theta (1+ cos theta))= cot theta`

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LHS= `(1+ cos  theta - sin^2 theta )/(sin theta (1+ cos theta)`

     =` ((1+ cos theta )- (1-cos^2 theta))/(sin theta(1+ cos theta))`

     =`(cos theta + cos^2 theta)/( sin theta ( 1+ cos theta))`

     =`(cos theta ( 1+ cos theta ))/ ( sin theta ( 1+ cos theta))`

     =`cos theta/ sin theta`

     = cot ЁЭЬГ
     = RHS
Hence, L.H.S. = R.H.S.

  

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рдкрд╛рда 8: Trigonometric Identities - Exercises 1

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