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Vapour Pressure of Solutions of Liquids in Liquids

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Estimated time: 6 minutes
Maharashtra State Board: Class 12

Law: Raoult's law

Statement: The partial vapour pressure of any volatile component of a solution is equal to the vapour pressure ofthe pure component multiplied by its mole fraction in the solution.

For a binary solution of two volatile components:

\[\mathrm{P}_{1}=\mathrm{P}_{1}^{0}x_{1}\quad\mathrm{and}\quad\mathrm{P}_{2}=\mathrm{P}_{2}^{0}x_{2}\]

Raoult's law Using Dalton's law of partial pressures, Total vapour pressure (P) is given by:

\[\mathrm{P}=\mathrm{P}_{1}+\mathrm{P}_{2}=\mathrm{P}_{1}^{0}x_{1}+\mathrm{P}_{2}^{0}x_{2}=\left(\mathrm{P}_{2}^{0}-\mathrm{P}_{1}^{0}\right)x_{2}+\mathrm{P}_{1}^{0}\]

Composition of vapour phase: If y1 and y2 are the mole fractions of the components 1 and 2, respectively, in the vapour phase; then using Dalton's law of partial pressures: P1 = y1P and P2 = y2P

Maharashtra State Board: Class 12

Key Points: Vapour Pressure of Solutions of Liquids in Liquids

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