HSC Commerce: Marketing and Salesmanship 11th Standard - Maharashtra State Board Question Bank Solutions for Mathematics and Statistics

Find n, if  `(1 × 2 + 2 × 3 + 3 × 4 + 4 × 5 + ...... + "upto n terms")/(1 + 2 + 3 + 4 + ....+ "upto n terms") = 100/3`

Find n, if `(1 × 2 + 2 × 3 + 3 × 4 + 4 × 5 + ...+ "upto n terms")/(1 + 2 + 3 + 4 + ...+ "upto n terms") = 100/3`

Find `sum_(r = 1) ^n (1+2+3+ ... + r)/(r)`

Find `sum_(r=1)^n (1 + 2 + 3 + ...+ r)/ r`

Find n, if `(1 xx 2 + 2 xx 3 + 3 xx 4 + 4 xx 5 + ... + "upto n terms")/(1 + 2 + 3 + 4 + ... + "upto n terms") = 100/3`

Find n, if `(1xx2 + 2xx 3 + 3xx4 + 4xx5 + ...+"upto n terms")/(1 + 2 + 3 + 4 + ...+"upto n terms") = 100/3`

Find `sum_(r=1)^n (1 + 2 + 3 + --- +r)/r`

Find n, if `(1 xx 2 + 2 xx 3 + 3 xx 4 + 4 xx 5 + ... + "upto  n terms")/(1 + 2 + 3 + 4 + ... + "upto n terms") = 100/3`.

Find `sum_(r = 1)^n (1 + 2 + 3 + ... + r)/(r)`

Find `sum_(r=1)^n(1+2+3+...+r)/r`

Find `sum_(r=1)^n   (1 + 2 + 3 + ... + r)/r`

Find `sum_(r=1)^n (1+2+3+...+r)/r`

Find \[\displaystyle\sum_{r=1}^{n}\frac{1 + 2 + 3 + ...+ r}{r}\]

Find n, if `(1xx2+2xx3+3xx4+4xx5 + ... + "upto n terms")/(1 + 2 + 3 + 4 + ... + "upto n terms") = 100/3`

Find n, if `(1 xx 2 + 2 xx 3 + 3 xx 4 + 4 xx 5 + ... + "upto n terms")/(1 + 2 +3 + 4 + ...+ "upto n terms") = 100/3`.

Find n, if `(1xx2+2xx3+3xx4+4xx5+...+"upto n terms")/(1+2+3+4+...+"upto n terms")=100/3`

Express the recurring decimal as a rational number.

3.4`bar56`

Find `sum_(r=1)^n (1+2+3+......+r)/r`

Find `sum _(r=1)^(n)  (1 + 2 + 3 + ... + r)/r`

Find `\underset{r=1}{\overset{n}{sum}} (1 + 2 + 3 +... + r)/(r)`