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Karnataka Board PUCPUC Science 2nd PUC Class 12

PUC Science 2nd PUC Class 12 - Karnataka Board PUC Question Bank Solutions for Mathematics

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Mathematics
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Define unit vector.

[10] Vectors
Chapter: [10] Vectors
Concept: undefined >> undefined

Using the properties of determinants, solve the following for x:

`|[x+2,x+6,x-1],[x+6,x-1,x+2],[x-1,x+2,x+6]|=0`

[3] Matrices
Chapter: [3] Matrices
Concept: undefined >> undefined

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Prove that  `|(yz-x^2,zx-y^2,xy-z^2),(zx-y^2,xy-z^2,yz-x^2),(xy-z^2,yz-x^2,zx-y^2)|`is divisible by (x + y + z) and hence find the quotient.

[3] Matrices
Chapter: [3] Matrices
Concept: undefined >> undefined

Using properties of determinants, prove that :

`|[1+a,1,1],[1,1+b,1],[1,1,1+c]|=abc + bc + ca + ab`

[3] Matrices
Chapter: [3] Matrices
Concept: undefined >> undefined

Prove that :

\[\begin{vmatrix}a & a + b & a + 2b \\ a + 2b & a & a + b \\ a + b & a + 2b & a\end{vmatrix} = 9 \left( a + b \right) b^2\]

 

[3] Matrices
Chapter: [3] Matrices
Concept: undefined >> undefined

x + y + z + w = 2
x − 2y + 2z + 2w = − 6
2x + y − 2z + 2w = − 5
3x − y + 3z − 3w = − 3

[3] Matrices
Chapter: [3] Matrices
Concept: undefined >> undefined

2x − 3z + w = 1
x − y + 2w = 1
− 3y + z + w = 1
x + y + z = 1

[3] Matrices
Chapter: [3] Matrices
Concept: undefined >> undefined

2x − y = 5
4x − 2y = 7

[3] Matrices
Chapter: [3] Matrices
Concept: undefined >> undefined

In the following matrix equation use elementary operation R2 → R2 + Rand the equation thus obtained:

\[\begin{bmatrix}2 & 3 \\ 1 & 4\end{bmatrix} \begin{bmatrix}1 & 0 \\ 2 & - 1\end{bmatrix} = \begin{bmatrix}8 & - 3 \\ 9 & - 4\end{bmatrix}\]
[3] Matrices
Chapter: [3] Matrices
Concept: undefined >> undefined

Use elementary column operation C2 → C2 + 2C1 in the following matrix equation : \[\begin{bmatrix} 2 & 1 \\ 2 & 0\end{bmatrix} = \begin{bmatrix}3 & 1 \\ 2 & 0\end{bmatrix}\begin{bmatrix}1 & 0 \\ - 1 & 1\end{bmatrix}\]

[3] Matrices
Chapter: [3] Matrices
Concept: undefined >> undefined
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