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Science (English Medium) Class 12 - CBSE Question Bank Solutions for Mathematics

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\[\vec{n}\] is a vector of magnitude \[\sqrt{3}\] and is equally inclined to an acute angle with the coordinate axes. Find the vector and Cartesian forms of the equation of a plane which passes through (2, 1, −1) and is normal to \[\vec{n}\] .

 

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
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The coordinates of the foot of the perpendicular drawn from the origin to a plane are (12, −4, 3). Find the equation of the plane.

 
[11] Three - Dimensional Geometry
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A plane passes through the point (1, −2, 5) and is perpendicular to the line joining the origin to the point

\[ \text{ 3 } \hat{i} + \hat{j} - \hat{k} .\] Find the vector and Cartesian forms of the equation of the plane.

 

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
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Find the equation of the plane that bisects the line segment joining the points (1, 2, 3) and (3, 4, 5) and is at right angle to it.

 
[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
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Show that the normals to the following pairs of planes are perpendicular to each other. 

x − y + z − 2 = 0 and 3x + 2y − z + 4 = 0 

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
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Show that the normals to the following pairs of planes are perpendicular to each other.

\[\vec{r} \cdot \left( 2 \hat{i}  - \hat{j}  + 3 \hat{k}  \right) = 5 \text{ and }  \vec{r} \cdot \left( 2 \hat{i}  - 2 \hat{j}  - 2 \hat{k}  \right) = 5\]
[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
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Show that the normal vector to the plane 2x + 2y + 2z = 3 is equally inclined to the coordinate axes.

 
[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
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Find the vector equation of a plane which is at a distance of 3 units from the origin and has \[\hat{k}\] as the unit vector normal to it.

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
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Find the vector equation of a plane which is at a distance of 5 units from the origin and which is normal to the vector  \[\hat{i}  - \text{2 } \hat{j}  -  \text{2 } \hat{k} .\]

 

[11] Three - Dimensional Geometry
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find the equation of the plane passing through the point (1, 2, 1) and perpendicular to the line joining the points (1, 4, 2) and (2, 3, 5). Find also the perpendicular distance of the origin from this plane

[11] Three - Dimensional Geometry
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Find the vector equation of the plane passing through the points (1, 1, 1), (1, −1, 1) and (−7, −3, −5).

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
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Find the vector equation of the plane passing through the points P (2, 5, −3), Q (−2, −3, 5) and R (5, 3, −3).

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
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Find the vector equation of the plane passing through points A (a, 0, 0), B (0, b, 0) and C(0, 0, c). Reduce it to normal form. If plane ABC is at a distance p from the origin, prove that \[\frac{1}{p^2} = \frac{1}{a^2} + \frac{1}{b^2} + \frac{1}{c^2} .\]

 

[11] Three - Dimensional Geometry
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Find the vector equation of the plane passing through the points (1, 1, −1), (6, 4, −5) and (−4, −2, 3).

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
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Find the vector equation of the plane passing through the points \[3 \hat{i}  + 4 \hat{j}  + 2 \hat{k} , 2 \hat{i} - 2 \hat{j} - \hat{k}  \text{ and }  7 \hat{i}  + 6 \hat{k}  .\]

 
[11] Three - Dimensional Geometry
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Determine the value of λ for which the following planes are perpendicular to each other.

\[\vec{r} \cdot \left( \hat{i}  + 2 \hat{j} + 3 \hat{k} \right) = 7 \text{ and }  \vec{r} \cdot \left( \lambda \hat{i} + 2 \hat{j}  - 7 \hat{k}  \right) = 26\]

 

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
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Determine the value of λ for which the following planes are perpendicular to each ot

 2x − 4y + 3z = 5 and x + 2y + λz = 5

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
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Determine the value of λ for which the following planes are perpendicular to each other. 

 3x − 6y − 2z = 7 and 2x + y − λz = 5

 
[11] Three - Dimensional Geometry
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Find the equation of a plane passing through the point (−1, −1, 2) and perpendicular to the planes 3x + 2y − 3z = 1 and 5x − 4y + z = 5.

 
[11] Three - Dimensional Geometry
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Obtain the equation of the plane passing through the point (1, −3, −2) and perpendicular to the planes x + 2y + 2z = 5 and 3x + 3y + 2z = 8.

 
[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
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