English Medium Class 10 - CBSE Question Bank Solutions for Mathematics

`sin^6 theta + cos^6 theta =1 -3 sin^2 theta cos^2 theta`

`sin^2 theta + cos^4 theta = cos^2 theta + sin^4 theta`

cosec⁴θ − cosec²θ = cot⁴θ + cot²θ

`(1+ tan^2 theta)/(1+ tan^2 theta)= (cos^2 theta - sin^2 theta)`

`(1-tan^2 theta)/(cot^2-1) = tan^2 theta`

`(tan theta)/((sec theta -1))+(tan theta)/((sec theta +1)) = 2 sec theta`

`(cot ^theta)/((cosec theta+1)) + ((cosec theta + 1))/cot theta = 2 sec theta`

`cot theta/((cosec  theta + 1) )+ ((cosec  theta +1 ))/ cot theta = 2 sec theta `

`(sec theta -1 )/( sec theta +1) = ( sin ^2 theta)/( (1+ cos theta )^2)`

`(sectheta- tan theta)/(sec theta + tan theta) = ( cos ^2 theta)/( (1+ sin theta)^2)`

`sqrt((1+sin theta)/(1-sin theta)) = (sec theta + tan theta)`

`sqrt((1-cos theta)/(1+cos theta)) = (cosec  theta - cot  theta)`

`sqrt((1+cos theta)/(1-cos theta)) + sqrt((1-cos theta )/(1+ cos theta )) = 2 cosec theta`

`(cos^3 theta +sin^3 theta)/(cos theta + sin theta) + (cos ^3 theta - sin^3 theta)/(cos theta - sin theta) = 2`

`sin theta/((cot theta + cosec  theta)) - sin theta /( (cot theta - cosec  theta)) =2`

` (sin theta - cos theta) / ( sin theta + cos theta ) + ( sin theta + cos theta ) / ( sin theta - cos theta ) = 2/ ((2 sin^2 theta -1))`

` (sin theta + cos theta )/(sin theta - cos theta ) + ( sin theta - cos theta )/( sin theta + cos theta) = 2/ ((1- 2 cos^2 theta))`

`(1+ cos  theta - sin^2 theta )/(sin theta (1+ cos theta))= cot theta`

`(cos  ec^theta + cot theta )/( cos ec theta - cot theta  ) = (cosec theta + cot theta )^2 = 1+2 cot^2 theta + 2cosec theta  cot theta`

`(sec theta + tan theta )/( sec theta - tan theta ) = ( sec theta + tan theta )^2 = 1+2 tan^2 theta + 25 sec theta tan theta `