English

Unpolarized light with intensity 10 is incident on two polaroids. The axis of the first polaroid makes on the angle of 50° with the vertical,

Advertisements
Advertisements

Question

Unpolarized light with intensity I0 is incident on two polaroids. The axis of the first polaroid makes on the angle of 50° with the vertical, and the axis of the second polaroid is horizontal. What is the intensity of the light after it has passed through the second polaroid?

Sum
Advertisements

Solution

According to Malus' law, when the unpolarized light with intensity l0 is incident on the first polarizer, the polarizer polarizes this incident light. The intensity of light becomes I1 = I0/2.

Now, I2 = I1 cos2θ

∴ I2 = `("l"_0/2) cos^2 (theta_2 - theta_1)`

`= ("l"_0/2) cos^2 (90° - 50°)`

∴ I2 = `("l"_0/2) cos^2 40°`

The intensity of light after it has passed through the second polaroid `("l"_0/2) cos^2 40° = "I"_0/2 (0.76660)^2`

= 0.2934 I0 

shaalaa.com
  Is there an error in this question or solution?
Chapter 7: Wave Optics - Exercises [Page 185]

APPEARS IN

Balbharati Physics [English] Standard 12 Maharashtra State Board
Chapter 7 Wave Optics
Exercises | Q 17. | Page 185
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×