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Question
Unpolarized light with intensity I0 is incident on two polaroids. The axis of the first polaroid makes on the angle of 50° with the vertical, and the axis of the second polaroid is horizontal. What is the intensity of the light after it has passed through the second polaroid?
Sum
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Solution
According to Malus' law, when the unpolarized light with intensity l0 is incident on the first polarizer, the polarizer polarizes this incident light. The intensity of light becomes I1 = I0/2.
Now, I2 = I1 cos2θ
∴ I2 = `("l"_0/2) cos^2 (theta_2 - theta_1)`
`= ("l"_0/2) cos^2 (90° - 50°)`
∴ I2 = `("l"_0/2) cos^2 40°`
The intensity of light after it has passed through the second polaroid `("l"_0/2) cos^2 40° = "I"_0/2 (0.76660)^2`
= 0.2934 I0
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