The area of a sector whose perimeter is four times its radius r units, is
2r2 sq. units
We know that perimeter of the sector= `2r+θ/360xx2pir`
We have given that perimeter of the sector is four times the radius.
Subtracting 2r from both sides of the equation,
Dividing both sides of the equation 2r we get,
Let us find the area of the sector.
∴ Area of the sector=`θ/360 pir^2`
Substituting `θpi/360=1` we get,
Area of the sector=`r^2`
Hence, area of the sector is `r^2 `sq.units
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