The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B0 = 510 nT. What is the amplitude of the electric field part of the wave? - Physics

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The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B0 = 510 nT. What is the amplitude of the electric field part of the wave?

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Solution

Amplitude of magnetic field of an electromagnetic wave in a vacuum,

B0 = 510 nT = 510 × 10−9 T

Speed of light in a vacuum, c = 3 × 108 m/s

Amplitude of electric field of the electromagnetic wave is given by the relation,

E = cB0

= 3 × 10× 510 × 10−9

= 153 N/C

Therefore, the electric field part of the wave is 153 N/C.

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Chapter 8: Electromagnetic Waves - Exercise [Page 286]

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NCERT Physics Class 12
Chapter 8 Electromagnetic Waves
Exercise | Q 8.7 | Page 286
NCERT Physics Class 12
Chapter 8 Electromagnetic Waves
Exercise | Q 7 | Page 286

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