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Question
Non-stoichiometric cuprous oxide, Cu2O can be prepared in laboratory. In this oxide, copper to oxygen ratio is slightly less than 2 : 1. Can you account for the fact that this substance is a p-type semiconductor?
Short Answer
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Solution
Some cuprous (Cu+) ions have been replaced by cupric (Cu2+) ions when the copper to oxygen ratio in Cu2O is less than 2 : 1. Since each Cu2+ ion entering the lattice must replace two Cu+ ions in order to preserve electrical neutrality, creating an electron-deficient hole, this suggests that there must be cation vacancies in the lattice. Consequently, the crystal would function as a p-type semiconductor and conduct electricity via the motion of electron-deficient (positive) holes.
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Properties of Solids: Electrical Properties - Conduction of Electricity in Semiconductors
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