# From a Rectangular Sheet of Paper Abcd with Ab = 40 Cm and Ad = 28 Cm, a Semicircular Portion with Bc as Diameter is Cut Off. Find the Area of the Remaining Paper. - Mathematics

Sum

From a rectangular sheet of paper ABCD with AB = 40 cm and AD = 28 cm, a semicircular portion with BC as diameter is cut off. Find the area of the remaining paper.

#### Solution

We know that the opposite sides of rectangle are equal

∴ AD = BC = 28 cm
Now, Radius of semicircular portion =1/2"BC = 14 "cm"

∴ Area of remaining paper = Area of rectangular sheet −Area of semicircular portion

= 40xx28-1/2(22/7xx14xx14)

= 1120 - 308

= 812 cm2

Hence, the area of the remaining paper is 812 cm2

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#### APPEARS IN

RS Aggarwal Secondary School Class 10 Maths
Chapter 18 Area of Circle, Sector and Segment
Exercise 18A | Q 27 | Page 820