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Question
For what values of x, `[1,2,1] [(1,2,0),(2,0,1),(1,0,2)][(0),(2),(x)]` = O?
Sum
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Solution
Here, `[(1,2,1)][(1,2,0), (2,0,1), (1,0,1)][(0),(2),(x)]` = O
⇒ `[(1,2,1)][(0 + 4 + 0),(0 + 0 + x),(0 + 0 + 2x)] = O`
`⇒ [(1,2,1)][(4),(x),(2x)] = O`
⇒ [4x + 2x + 2x] = O
⇒ 4x + 4 = O
⇒ 4x = -4
∴ `x = -4/4 = -1`
= x = -1
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