Find the number of oscillations performed per minute by a magnet is vibrating in the plane of a uniform field of 1.6 × 10-5 Wb/m2. - Physics

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Sum

Find the number of oscillations performed per minute by a magnet is vibrating in the plane of a uniform field of 1.6 × 10-5 Wb/m2. The magnet has a moment of inertia 3 × 10-6 kg/m2 and magnetic moment 3 A m2.

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Solution

Data: B = 1.6 x 10-5 T, I = 3 x 10-6 kg/m2 , µ = 3 A m2

The period of oscillation, T = `2πsqrt("I"/(μ"B"_"h")`

∴ The frequency of oscillation is

f = `1/(2π)sqrt((μ"B")/("I"))`

∴ The number of oscillations per minute

= 60f = `60/(2π)sqrt((3(1.6xx10^-5))/(3xx10^-6))=60/(2π)sqrt(16)=120/3.142`

= 38.19 osc/min.

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Chapter 5: Oscillations - Exercises [Page 130]

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Balbharati Physics 12th Standard HSC Maharashtra State Board
Chapter 5 Oscillations
Exercises | Q 22 | Page 130

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