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Question
Find the angle between hour-hand and minute-hand in a clock at ten past eleven.
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Solution
The angle between any two consecutive numbers of a clock is `(360°)/(12)` = 30°.
If the minute-hand is at 2 and hour-hand is at 11.
Angle between marks 11 and 2 = 3 × 30° = 90°
But at 10 past eleven, i.e., at 11.10, the hour-hand has moved 10 minutes towards 12.
In 60 minutes, the hour-hand covers 30°, therefore in 10 minutes, it covers `(30/6)^circ` = 5°
∴ The angle between the two hands of the clock at ten past eleven = 90° – 5° = 85°.
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