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Evaluate the following integrals: ∫_2^7 sqrtx/(sqrtx + sqrt(9 − x))dx - Mathematics and Statistics

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Questions

Evaluate the following integrals:

 `int_2^7 sqrt(x)/(sqrt(x) + sqrt(9 - x))*dx`

Evaluate: `∫_2^7 sqrtx/(sqrtx + sqrt(9 − x))dx`

Evaluate
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Solution

Let I = `int_2^7 sqrt(x)/(sqrt(x) + sqrt(9 - x))dx`     ...[i]

= `int_2^7 sqrt(2 + 7 - x)/(sqrt(2 + 7 - x) + sqrt(9 - (2 + 7 - x)))dx`            `...[∵ int_a^b f(x)dx = int_a^b f(a + b - x) dx]`

∴ I = `int_2^7 sqrt(9 - x)/(sqrt(9 - x) + sqrt(x))dx`    ...[ii]

Adding [i] and [ii], we get

2I = `int_2^7 sqrt(x)/(sqrt(x) + sqrt(9 - x))dx + int_2^7 sqrt(9 - x)/(sqrt(9 - x) + sqrt(x))dx` 

= `int_2^7 (sqrt(x) + sqrt(9 - x))/(sqrt(x) + sqrt(9 - x)) dx`

= `int_2^7 1dx`

= `[x]_2^7`

∴ 2I = 7 – 2

∴ 2I = 5

∴ I = `(5)/(2)`

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Chapter 6: Definite Integration - EXERCISE 6.2 [Page 148]
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