Question

Evaluate the following:

`tan^-1(tan  (7pi)/6)`

Answer 1

We know that

`tan^-1(tantheta)=theta,   -pi/2<theta<pi/2`

We have 

`tan^-1(tan  (7pi)/6)=tan^-1[tan(pi+pi/6)]`

`=tan^-1[tan(pi/6)]`

`=pi/6`