**Answer the following question.**

Define the term, "refractive index" of a medium. Verify Snell's law of refraction when a plane wavefront is propagating from a denser to a rarer medium.

#### Solution

Refractive index of a medium may be defined as the ratio of the speed of light in air and the speed of light in the given medium. It doesn’t have a unit.

**Refraction On The Basis Of Wave Theory**

Consider any point Q on the incident wavefront.

Suppose when disturbance from point P on incident wavefront reaches point P' on the refracted wavefront, the disturbance from point Q reaches Q' on the refracting surface XY.

Since P'A' represents the refracted wavefront, the time taken by light to travel from a point on incident wavefront to the corresponding point on the refracted wavefront should always be the same. Now, the time taken by light to go from Q to Q' will be

`t = "QK"/c + "KQ'"/"v"` ....(i)

In right-angled ΔAQK,

∠QAK = i**∴** QK = AK sin i … (ii)

In right-angled ΔP'Q'K,

∠Q'P'K = r

KQ' = KP' sin r ...(iii)

**Substituting (ii) and (iii) in equation (i),**

`t = ("AK"sin i)/(c) + ("KP"'sin r)/("v")`

Or, `t = ("AK"sin i)/(c) + (("AP'"- "AK")sin r)/v ....(∵ "KP"' = "AP"' - "AK")`

Or, `t = ("AP"')/(c) sin r + "AK" (sin i/c - sin r /"v")` ....(iv)

The rays from different points on the incident wavefront will take the same time to reach the corresponding points on the refracted wavefront i.e., t given by equation (iv) is independent of AK. It will happen so, if

`sin"i"/c - sin"r"/"v"` = 0

`sin "i"/sin "r" = c / "v"`

However, `c/"v" = mu`

**∴ **`mu = sin"i"/sin"r"`

This is the Snell’s law for refraction of light.