An object 5 cm is placed at a distance of 20 cm in front of a convex mirror of radius of curvature 30 cm. Find the position, nature and size of the image.
Object distance, u= – 20 cm
Object height, h= 5 cm
Radius of curvature, R= 30 cm
Radius of curvature = 2 × Focal length
f= 15 cm
According to the mirror formula,
The positive value of v indicates that the image is formed behind the mirror.
Magnificatiom m=`"Image Distance"/"Object Distance"=-8.57/(-20)=0.428`
The positive value of magnification indicates that the image formed is virtual
Magnificatiom m=`"Height of image"/"Height of Object"=(h')/h`
h'=m x h=0.428 x 5=2.14 cm
The positive value of image height indicates that the image formed is erect.
Therefore, the image formed is virtual, erect, and smaller in size.
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