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Chapters
1: Real Numbers
Algebra
2: Polynomials
3: Linear Equations in Two Variables
4: Quadratic Equations
5: Arithmetic Progression
Coordinate Geometry
6: Coordinate Geometry
Geometry
7: Triangles
8: Circles
9: Constructions
Trigonometry
10: Trignometric Ratios
▶ 11: T-Ratios of Some Particular Angles
12: Trigonometric Ratios of Some Complemantary Angles
13: Trigonometric identities
14: Heights and Distances
Mensuration
15: Perimeter And Area of Plane Figures
16: Area of Circle, Sector and Segment
17: Volumes and Surface Areas of Solids
Statistics and Probability
18: Mean, Median, Mode of Grouped Data, Cumulative Frequency Graph and Ogive
19: Probability
Chapter 20: Additional Questions
![R.S. Aggarwal solutions for माठेमटिक्स [इंग्रजी] इयत्ता १० chapter 11 - T-Ratios of Some Particular Angles - Shaalaa.com](/images/mathematics-english-class-10_6:8f062ea57bdf49abb4f6d22550b39d56.jpg "R.S. Aggarwal solutions for माठेमटिक्स [इंग्रजी] इयत्ता १० chapter 11 - T-Ratios of Some Particular Angles")
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Solutions for Chapter 11: T-Ratios of Some Particular Angles
Below listed, you can find solutions for Chapter 11 of CBSE, Karnataka Board R.S. Aggarwal for माठेमटिक्स [इंग्रजी] इयत्ता १०.
R.S. Aggarwal solutions for माठेमटिक्स [इंग्रजी] इयत्ता १० 11 T-Ratios of Some Particular Angles Exercises
Evaluate:
sin600 cos300 + cos600 sin300
Evaluate:
cos600 cos300− sin600 sin300
Evaluate:
cos450 cos300 + sin450 sin300
Evaluate:
`(sin30°)/(cos 45°)+(cot45°)/(sec60° )- (sin60°)/(tan45°)+(cos30°)/(sin90°)`
Evaluate:
`(5 cos^2 60^circ + 4 sec^2 30^circ - tan^2 45^circ)/(sin^2 30^circ + cos^2 30^circ)`
Evaluate:
`2cos^2 60^0+3 sin^2 45^0 - 3 sin^2 30^0 + 2 cos^2 90 ^0`
Evaluate:
`cot^2 30^0-2cos^2 30^0-3/4 sec^2 45^0 +1/4 cosec^2 30^0`
Evaluate:
`(sin^2 30^0 + 4 cot^2 45^0-sec^2 60^0)(cosec^2 45^0 sec^2 30^0)`
Evaluate:
`4/(cot^2 30^0) +1/(sin^2 30^0) -2 cos^2 45^0 - sin^2 0^0`
Show that:
(i)` (1-sin 60^0)/(cos 60^0)=(tan60^0-1)/(tan60^0+1)`
Show that:
(ii) `(cos30^0+sin 60^0)/(1+sin30^0+cos60^0)=cos 30^0`
Verify each of the following:
(i)`sin 60^0 cos 30^0-cos 60^0 sin 30^0`
Verify each of the following:
(ii)`cos 60^0 cos 30^0+ sin 60^0 sin30^0`
Verify each of the following:
(iii) `2 sin 30^0 cos 30^0`
Verify each of the following:
(iv) `2 sin 45^0 cos 45^0`
If A = 45°, verify that sin 2A = 2 sin A cos A.
If A = 450 , verify that:
(ii) cos 2A = 2 cos2 A – 1 = 1 – 2 sin2 A
If A = 300 , verify that:
(i) sin 2A = `(2 tan A)/(1+tan^2A)`
If A = 300 , verify that:
(ii) cos 2A = `(1- tan^2A)/(1+tan^2A)`
If A = 300 , verify that:
(iii) tan 2A = `(2tanA)/(1-tan^2A)`
If A = 600 and B = 300, verify that:
(i) sin (A + B) = sin A cos B + cos A sin B
If A = 600 and B = 300, verify that:
cos (A + B) = cos A cos B - sin A sin B
If A = 60° and B = 30°, verify that sin (A – B) = sin A cos B – cos A sin B.
If A = 600 and B = 300, verify that:
(ii) cos (A – B) = cos A cos B + sin A sin B
If A = 60° and B = 30°, verify that `tan (A - B) = (tan A - tan B)/(1 + tan A tan B)`.
If A and B are acute angles such that tan A =`1/3, tan B = 1/2 and tan (A + B) =` show that `A+B = 45^0`
Using the formula, tan 2A =`(2 tan A )/(1- tan^2 A)` find the value of tan 600, it being given that tan 300 = `1/sqrt(3)`.
Using the formula, cos A = `sqrt((1+cos2A)/2) ,`find the value of cos 300, it being given that cos 600 = `1/2`.
Using the formula, sin A = `sqrt((1-cos 2A)/2) ` find the value of sin 300, it being given that cos 600 = `1/2`
In the adjoining figure, ΔABC is a right-angled triangle in which ∠B = 900, ∠300 and AC = 20cm. Find (i) BC, (ii) AB.
In the adjoining figure, ΔABC is right-angled at B and ∠A = 300. If BC = 6cm, find (i) AB, (ii) AC.
In the adjoining figure, ΔABC is right-angled at B and ∠A = 450. If AC = 3`sqrt(2)`cm, find (i) BC, (ii) AB.
If sin (A + B) = 1 and cos (A – B) = 1, 00 ≤ (A + B) ≤ 900 and A > B, then find A and B.
If sin (A – B) = `1/2` and cos (A + B) = `1/2, 0^0 ≤ (A + B) ≤ 90^0` and A > B, then find A and B.
If tan (A + B) = `sqrt3` and tan (A – B) = `1/sqrt3`; 0° < A + B ≤ 90°; A > B, find A and B.
If 3x = cosecθ = and `3/x= cottheta` find the value of 3`(x^2-1/x^2)`.
If sin (A+B) = sin A cos B + cos A sin B and cos (A-B) = cos A cos B + sin A sin B
(i) sin (750)
(ii) cos (150)
Solutions for 11: T-Ratios of Some Particular Angles
R.S. Aggarwal solutions for माठेमटिक्स [इंग्रजी] इयत्ता १० chapter 11 - T-Ratios of Some Particular Angles
Shaalaa.com has the CBSE, Karnataka Board Mathematics माठेमटिक्स [इंग्रजी] इयत्ता १० CBSE, Karnataka Board solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. R.S. Aggarwal solutions for Mathematics माठेमटिक्स [इंग्रजी] इयत्ता १० CBSE, Karnataka Board 11 (T-Ratios of Some Particular Angles) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.
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Concepts covered in माठेमटिक्स [इंग्रजी] इयत्ता १० chapter 11 T-Ratios of Some Particular Angles are Trigonometric Ratios, Trigonometric Ratios of Specific Angles, Trigonometric Identities (Square Relations), Trigonometry, Relation Among Trigonometric Ratios, Trigonometric Ratios, Trigonometric Ratios of Specific Angles, Trigonometric Identities (Square Relations), Trigonometry, Relation Among Trigonometric Ratios.
Using R.S. Aggarwal माठेमटिक्स [इंग्रजी] इयत्ता १० solutions T-Ratios of Some Particular Angles exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in R.S. Aggarwal Solutions are essential questions that can be asked in the final exam. Maximum CBSE, Karnataka Board माठेमटिक्स [इंग्रजी] इयत्ता १० students prefer R.S. Aggarwal Textbook Solutions to score more in exams.
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