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SSC (English Medium) इयत्ता १० वी - Maharashtra State Board Question Bank Solutions

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In ΔABC, ∠ABC = 90° and ∠ACB = θ. Then write the ratios of sin θ and tan θ from the figure.

[6] Trigonometry
Chapter: [6] Trigonometry
Concept: undefined >> undefined

Prove that sec θ + tan θ = `cos θ/(1 - sin θ)`.

Proof: L.H.S. = sec θ + tan θ

= `1/square + square/square`

= `square/square`  ......`(∵ sec θ = 1/square, tan θ = square/square)`

= `((1 + sin θ) square)/(cos θ  square)`  ......[Multiplying `square` with the numerator and denominator]

= `(1^2 - square)/(cos θ  square)`

= `square/(cos θ  square)`

= `cos θ/(1 - sin θ)` = R.H.S.

∴ L.H.S. = R.H.S.

∴ sec θ + tan θ = `cos θ/(1 - sin θ)`

[6] Trigonometry
Chapter: [6] Trigonometry
Concept: undefined >> undefined

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Find the value of sin 0° + cos 0° + tan 0° + sec 0°.

[6] Trigonometry
Chapter: [6] Trigonometry
Concept: undefined >> undefined

Find the value of sin 45° + cos 45° + tan 45°.

[6] Trigonometry
Chapter: [6] Trigonometry
Concept: undefined >> undefined

What will be the value of sin 45° + `1/sqrt(2)`?

[6] Trigonometry
Chapter: [6] Trigonometry
Concept: undefined >> undefined

In the given figure, if sin θ = `7/13`, which angle will be θ?

[6] Trigonometry
Chapter: [6] Trigonometry
Concept: undefined >> undefined

Prove that: cot θ + tan θ = cosec θ·sec θ

Proof: L.H.S. = cot θ + tan θ

= `square/square + square/square`  ......`[∵ cot θ = square/square, tan θ = square/square]`

= `(square + square)/(square xx square)`  .....`[∵ square + square = 1]`

= `1/(square xx square)`

= `1/square xx 1/square`

= cosec θ·sec θ  ......`[∵ "cosec"  θ = 1/square, sec θ = 1/square]`

= R.H.S.

∴ L.H.S. = R.H.S.

∴ cot θ + tan θ = cosec·sec θ

[6] Trigonometry
Chapter: [6] Trigonometry
Concept: undefined >> undefined

If sec θ = `1/2`, what will be the value of cos θ?

[6] Trigonometry
Chapter: [6] Trigonometry
Concept: undefined >> undefined

Find will be the value of cos 90° + sin 90°.

[6] Trigonometry
Chapter: [6] Trigonometry
Concept: undefined >> undefined

In ∆RST, ∠S = 90°, ∠T = 30°, RT = 12 cm, then find RS.

[2] Pythagoras Theorem
Chapter: [2] Pythagoras Theorem
Concept: undefined >> undefined

Write down the equation of a line whose slope is 3/2 and which passes through point P, where P divides the line segment AB joining A(-2, 6) and B(3, -4) in the ratio 2 : 3.

[5] Co-ordinate Geometry
Chapter: [5] Co-ordinate Geometry
Concept: undefined >> undefined

ΔRST ~ ΔUAY, In ΔRST, RS = 6 cm, ∠S = 50°, ST = 7.5 cm. The corresponding sides of ΔRST and ΔUAY are in the ratio 5 : 4. Construct ΔUAY.

[5] Co-ordinate Geometry
Chapter: [5] Co-ordinate Geometry
Concept: undefined >> undefined

Construct the circumcircle and incircle of an equilateral triangle ABC with side 6 cm and centre O. Find the ratio of radii of circumcircle and incircle.

[5] Co-ordinate Geometry
Chapter: [5] Co-ordinate Geometry
Concept: undefined >> undefined

Construct the circumcircle and incircle of an equilateral ∆XYZ with side 6.5 cm and centre O. Find the ratio of the radii of incircle and circumcircle.

[5] Co-ordinate Geometry
Chapter: [5] Co-ordinate Geometry
Concept: undefined >> undefined

Given below is the triangle and length of line segments. Identify in the given figure, ray PM is the bisector of ∠QPR.

[1] Similarity
Chapter: [1] Similarity
Concept: undefined >> undefined

Given below is the triangle and length of line segments. Identify in the given figure, ray PM is the bisector of ∠QPR.

[1] Similarity
Chapter: [1] Similarity
Concept: undefined >> undefined

Given below is the triangle and length of line segments. Identify in the given figure, ray PM is the bisector of ∠QPR.

[1] Similarity
Chapter: [1] Similarity
Concept: undefined >> undefined

In ∆MNP, NQ is a bisector of ∠N. If MN = 5, PN = 7 MQ = 2.5 then find QP. 

[1] Similarity
Chapter: [1] Similarity
Concept: undefined >> undefined

Measures of some angles in the figure are given. Prove that `"AP"/"PB" = "AQ"/"QC"`.

[1] Similarity
Chapter: [1] Similarity
Concept: undefined >> undefined

Find QP using given information in the figure.

[1] Similarity
Chapter: [1] Similarity
Concept: undefined >> undefined
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