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ICSE ICSE Class 8 - CISCE Question Bank Solutions

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Solve the following equation:

`(3"x" + 2)/("x" - 6) = -7`

[3.4] Linear Equations in One Variable
Chapter: [3.4] Linear Equations in One Variable
Concept: undefined >> undefined

The length of a rectangle is 16 cm and its perimeter is equal to the perimeter of a square with side 12.5 cm. Find the area of the rectangle.

[5.1] Area of a Trapezium and a Polygon
Chapter: [5.1] Area of a Trapezium and a Polygon
Concept: undefined >> undefined

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A certain sum of money invested for 5 years at 8% p.a. simple interest earns an interest of ₹ 12,000. Find:
(i) the sum of money.
(ii) the compound interest earned by this money in two years and at 10% p.a. compound interest.

[2.3] Interest
Chapter: [2.3] Interest
Concept: undefined >> undefined

Each side of a rectangle is doubled. Find the ratio between :
(i) perimeters of the original rectangle and the resulting rectangle.
(ii) areas of the original rectangle and the resulting rectangle.

[5.1] Area of a Trapezium and a Polygon
Chapter: [5.1] Area of a Trapezium and a Polygon
Concept: undefined >> undefined

In each of the following cases, ABCD is a square and PQRS is a rectangle. Find, in each case, the area of the shaded portion.
(All measurements are in metre).

(i)

(ii)

[5.1] Area of a Trapezium and a Polygon
Chapter: [5.1] Area of a Trapezium and a Polygon
Concept: undefined >> undefined

The length and the breadth of a rectangular field are in the ratio 5: 4 and its area is 3380 m2. Find the cost of fencing it at the rate of ₹75 per m.

[5.1] Area of a Trapezium and a Polygon
Chapter: [5.1] Area of a Trapezium and a Polygon
Concept: undefined >> undefined

A path of uniform width, 2.5 m, runs around the inside of a rectangular field 30 m by 27 m. Find the area of the path.

[5.1] Area of a Trapezium and a Polygon
Chapter: [5.1] Area of a Trapezium and a Polygon
Concept: undefined >> undefined

A rectangular field is 30 m in length and 22m in width. Two mutually perpendicular roads, each 2.5 m wide, are drawn inside the field so that one road is parallel to the length of the field and the other road is parallel to its width. Calculate the area of the crossroads.

[5.1] Area of a Trapezium and a Polygon
Chapter: [5.1] Area of a Trapezium and a Polygon
Concept: undefined >> undefined

The length and the breadth of a conference hall are in the ratio 7: 4 and its perimeter is 110 m. Find:

(i) area of the floor of the hall.
(ii) a number of tiles, each a rectangle of size 25 cm x 20 cm, required for the flooring of the hall.
(iii) the cost of the tiles at the rate of ₹ 1,400 per hundred tiles.

[5.1] Area of a Trapezium and a Polygon
Chapter: [5.1] Area of a Trapezium and a Polygon
Concept: undefined >> undefined

In which of the following table, x and y vary directly:

x 3 5 8 11
y 4.5 7.5 12 16.5
[2.4] Direct and Inverse Variations
Chapter: [2.4] Direct and Inverse Variations
Concept: undefined >> undefined

In which of the following table, x and y vary directly:

x 16 30 40 56
y 32 60 80 84
[2.4] Direct and Inverse Variations
Chapter: [2.4] Direct and Inverse Variations
Concept: undefined >> undefined

Solve the following equation:

`(3"x")/("x" + 6) - "x"/("x" + 5) = 2`

[3.4] Linear Equations in One Variable
Chapter: [3.4] Linear Equations in One Variable
Concept: undefined >> undefined

In which of the following table, x and y vary directly:

x 27 45 54 75
y 81 180 216 225
[2.4] Direct and Inverse Variations
Chapter: [2.4] Direct and Inverse Variations
Concept: undefined >> undefined

Solve the following equation:

`1/("x - 1") + 2/("x" - 2) = 3/("x" - 3)`

[3.4] Linear Equations in One Variable
Chapter: [3.4] Linear Equations in One Variable
Concept: undefined >> undefined

Solve the following equation:

`("x" - 1)/("7x" - 14) = ("x" - 3)/("7x" - 26)`

[3.4] Linear Equations in One Variable
Chapter: [3.4] Linear Equations in One Variable
Concept: undefined >> undefined

Solve the following equation:

`1/("x" - 1) - 1/"x" = 1/("x" + 3) - 1/("x" + 4)`

[3.4] Linear Equations in One Variable
Chapter: [3.4] Linear Equations in One Variable
Concept: undefined >> undefined

Solve: `"2x"/3 - ("x" - 1)/6 + ("7x" - 1)/4 = 2 1/6` Hence, find the value of 'a', if `1/"a" + 5"x" = 8`

[3.4] Linear Equations in One Variable
Chapter: [3.4] Linear Equations in One Variable
Concept: undefined >> undefined

Solve: `(4-3"x")/5 + (7 - "x")/3 + 4 1/3 = 0` Hence, find the value of 'p', if 3p - 2x + 1 = 0

[3.4] Linear Equations in One Variable
Chapter: [3.4] Linear Equations in One Variable
Concept: undefined >> undefined

Solve: 0.25 + `1.95/"x" = 0.9`

[3.4] Linear Equations in One Variable
Chapter: [3.4] Linear Equations in One Variable
Concept: undefined >> undefined

Solve:

`5x − (4x + (5x -  4)/7) = (4x - 14)/3`

[3.4] Linear Equations in One Variable
Chapter: [3.4] Linear Equations in One Variable
Concept: undefined >> undefined
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