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प्रश्न
Solve: `(4-3"x")/5 + (7 - "x")/3 + 4 1/3 = 0` Hence, find the value of 'p', if 3p - 2x + 1 = 0
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उत्तर
`=> (4-3"x")/5 + (7 - "x")/3 + 4 1/3 = 0`
`=> (4-3"x")/5 + (7 - "x")/3 + 13/3 = 0`
`(12 - 9"x" + 35 - 5"x" + 65 = 0)/15` ...(L.C.M. of 5, 3, 3 = 15)
-14x + 112 = 0
⇒ -14x = -112
⇒ x = `(-112)/-14` = 8
Hence x = 8
Now, 3p – 2x + 1=0
⇒ 3p – 2 x 8 + 1 = 0
⇒ 3p – 16 + 1 =0
⇒ 3p – 15 = 0.
⇒ 3p=15
⇒ p = 5
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