Advertisements
Advertisements
प्रश्न
Two consecutive natural numbers are such that one-fourth of the smaller exceeds one-fifth of the greater by 1. Find the numbers.
Advertisements
उत्तर
Let two consecutive natural numbers = x, x+1
∴ One-fourth of the smaller = `"x"/4`
one-fifth of the greater = `("x" + 1)/5`
According to the statement:
`"x"/4 = ("x" + 1)/5 + 1 => "x"/4 - ("x" + 1)/5 = 1`
`=> (5"x" - 4("x" + 1))/20 = 1 => (5"x" - 4"x" - 4)/20 = 1`
`=> ("x" - 4)/20 = 1`
⇒ x - 4 = 20 ...(Cross multiplying)
⇒ x = 20 + 4 ⇒ x = 24
∴ x + 1 = 24 + 1 = 25
Two consecutive numbers are 24 and 25
APPEARS IN
संबंधित प्रश्न
Solve the following equation:
`(3"x")/("x" + 6) - "x"/("x" + 5) = 2`
Solve: `(4-3"x")/5 + (7 - "x")/3 + 4 1/3 = 0` Hence, find the value of 'p', if 3p - 2x + 1 = 0
Separate 178 into two parts so that the first part is 8 less than twice the second part.
The difference of two numbers is 3 and the difference of their squares is 69. Find the numbers.
The present age of a man is twice that of his son. Eight years hence, their ages will be in the ratio 7 : 4. Find their present ages
Solve:
`1/10 - 7/x = 35`
Solve:
13(x − 4) - 3(x − 9) − 5(x + 4) = 0
Given that x ≥ y. Fill in the blank with suitable inequality sign
x + 6 `square` y + 6
When x is an integer, the solution set for x ≤ 0 are −1, −2, ...
An artist can spend any amount between ₹ 80 to ₹ 200 on brushes. If cost of each brush is ₹ 5 and there are 6 brushes in each packet, then how many packets of brush can the artist buy?
