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What will be the conjugate bases for the following Bronsted acids:
HF, H2SO4 and \[\ce{HCO^-_3}\]?
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Which hybrid orbitals are used by carbon atoms in the following molecules?
CH3–CH=CH2
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Which hybrid orbitals are used by carbon atoms in the following molecules?
CH3-CH2-OH
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Which hybrid orbitals are used by carbon atoms in the following molecules?
CH3-CHO
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Which hybrid orbitals are used by carbon atoms in the following molecules?
CH3COOH
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What will be the molarity of a solution, which contains 5.85 g of NaCl(s) per 500 mL?
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If 500 mL of a 5 M solution is diluted to 1500 mL, what will be the molarity of the solution obtained?
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If the concentration of glucose \[\ce{(C6H12O6)}\] in blood is 0.9 g L–1, what will be the molarity of glucose in blood?
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What will be the molality of the solution containing 18.25 g of \[\ce{HCl}\] gas in 500 g of water?
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Sulphuric acid reacts with sodium hydroxide as follows:
\[\ce{H2SO4 + 2NaOH -> Na2SO4 + 2H2O}\]
When 1 L of 0.1 M sulphuric acid solution is allowed to react with 1 L of 0.1 M sodium hydroxide solution, the amount of sodium sulphate formed and its molarity in the solution obtained is:
(i) 0.1 mol L–1
(ii) 7.10 g
(iii) 0.025 mol L–1
(iv) 3.55 g
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Which of the following solutions have the same concentration?
(i) \[\ce{20 g of NaOH in 200 mL of solution}\]
(ii) \[\ce{0.5 mol of KCl in 200 mL of solution}\]
(iii) \[\ce{40 g of NaOH in 100 mL of solution}\]
(iv) \[\ce{20 g of KOH in 200 mL of solution}\]
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Which of the following terms are unitless?
(i) Molality
(ii) Molarity
(iii) Mole fraction
(iv) Mass percent
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What is the difference between molality and molarity?
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If 4 g of \[\ce{NaOH}\] dissolves in 36 g of \[\ce{H2O}\], calculate the mole fraction of each component in the solution. Also, determine the molarity of solution (specific gravity of solution is 1g mL–1).
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Match the following physical quantities with units
| Physical quantity | Unit |
| (i) Molarity | (a) g mL–1 |
| (ii) Mole fraction | (b) mol |
| (iii) Mole | (c) Pascal |
| (iv) Molality | (d) Unitless |
| (v) Pressure | (e) mol L–1 |
| (vi) Luminous intensity | (f) Candela |
| (vii) Density | (g) mol kg–1 |
| (viii) Mass | (h) Nm–1 |
| (i) kg |
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\[\ce{BF3}\] does not have proton but still acts as an acid and reacts with \[\ce{NH3}\]. Why is it so? What type of bond is formed between the two?
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A reaction between ammonia and boron trifluoride is given below: \[\ce{NH3 + BF3 -> H3N : BF3}\] Identify the acid and base in this reaction. Which theory explains it? What is the hybridisation of B and N in the reactants?
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Match the following species with the corresponding conjugate acid:
| Species | Conjugate acid |
| (i) \[\ce{NH3}\] | (a) \[\ce{CO^{2-}3}\] |
| (ii) \[\ce{HCO^{-}3}\] | (b) \[\ce{NH^{+}4}\] |
| iii) \[\ce{H2O}\] | (c) \[\ce{H3O+}\] |
| (iv) \[\ce{HSO^{-}4}\] | (d) \[\ce{H2SO4}\] |
| (e) \[\ce{H2CO3}\] |
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Match the type of mixture of compounds in Column I with the technique of separation/purification given in Column II.
| Column I | Column II |
| (i) Two solids which have different solubilities in a solvent and which do not undergo reaction when dissolved in it. | (a) Steam distillation |
| (ii) Liquid that decomposes at its boiling point | (b) Fractional distillation |
| (iii) Steam volatile liquid | (c) Simple distillation |
| (iv) Two liquids which have boiling points close to each other | (d) Distillation under reduced pressure |
| (v) Two liquids with large difference in boiling points. | (e) Crystallisation |
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Assertion (A): Simple distillation can help in separating a mixture of propan-1-ol (boiling point 97°C) and propanone (boiling point 56°C).
Reason (R): Liquids with a difference of more than 20°C in their boiling points can be separated by simple distillation.
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