मराठी

Arts (English Medium) इयत्ता ११ - CBSE Question Bank Solutions

Advertisements
[object Object]
[object Object]
विषय
मुख्य विषय
अध्याय

Please select a subject first

Advertisements
Advertisements
< prev  4441 to 4460 of 9258  next > 

Find the rational numbers having the following decimal expansion: 

\[0 . 6\overline8\]

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

One side of an equilateral triangle is 18 cm. The mid-points of its sides are joined to form another triangle whose mid-points, in turn, are joined to form still another triangle. The process is continued indefinitely. Find the sum of the (i) perimeters of all the triangles. (ii) areas of all triangles.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

Advertisements

Find an infinite G.P. whose first term is 1 and each term is the sum of all the terms which follow it.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

The sum of first two terms of an infinite G.P. is 5 and each term is three times the sum of the succeeding terms. Find the G.P.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

Show that in an infinite G.P. with common ratio r (|r| < 1), each term bears a constant ratio to the sum of all terms that follow it.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If S denotes the sum of an infinite G.P. S1 denotes the sum of the squares of its terms, then prove that the first term and common ratio are respectively

\[\frac{2S S_1}{S^2 + S_1}\text {  and } \frac{S^2 - S_1}{S^2 + S_1}\]

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If a, b, c are in G.P., prove that log a, log b, log c are in A.P.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If a, b, c are in G.P., prove that \[\frac{1}{\log_a m}, \frac{1}{\log_b m}, \frac{1}{\log_c m}\] are in A.P.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

Find k such that k + 9, k − 6 and 4 form three consecutive terms of a G.P.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

Three numbers are in A.P. and their sum is 15. If 1, 3, 9 be added to them respectively, they form a G.P. Find the numbers.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

The sum of three numbers which are consecutive terms of an A.P. is 21. If the second number is reduced by 1 and the third is increased by 1, we obtain three consecutive terms of a G.P. Find the numbers.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

The sum of three numbers a, b, c in A.P. is 18. If a and b are each increased by 4 and c is increased by 36, the new numbers form a G.P. Find a, b, c.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

The sum of three numbers in G.P. is 56. If we subtract 1, 7, 21 from these numbers in that order, we obtain an A.P. Find the numbers.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If a, b, c are in G.P., prove that:

a (b2 + c2) = c (a2 + b2)

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If a, b, c are in G.P., prove that:

\[a^2 b^2 c^2 \left( \frac{1}{a^3} + \frac{1}{b^3} + \frac{1}{c^3} \right) = a^3 + b^3 + c^3\]

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If a, b, c are in G.P., prove that:

\[\frac{(a + b + c )^2}{a^2 + b^2 + c^2} = \frac{a + b + c}{a - b + c}\]

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If a, b, c are in G.P., prove that:

\[\frac{1}{a^2 - b^2} + \frac{1}{b^2} = \frac{1}{b^2 - c^2}\]

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If a, b, c are in G.P., prove that:

(a + 2b + 2c) (a − 2b + 2c) = a2 + 4c2.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If a, b, c, d are in G.P., prove that:

\[\frac{ab - cd}{b^2 - c^2} = \frac{a + c}{b}\]

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If a, b, c, d are in G.P., prove that:

 (a + b + c + d)2 = (a + b)2 + 2 (b + c)2 + (c + d)2

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined
< prev  4441 to 4460 of 9258  next > 
Advertisements
Advertisements
CBSE Arts (English Medium) इयत्ता ११ Question Bank Solutions
Question Bank Solutions for CBSE Arts (English Medium) इयत्ता ११ Accountancy
Question Bank Solutions for CBSE Arts (English Medium) इयत्ता ११ Business Studies
Question Bank Solutions for CBSE Arts (English Medium) इयत्ता ११ Computer Science (C++)
Question Bank Solutions for CBSE Arts (English Medium) इयत्ता ११ Economics
Question Bank Solutions for CBSE Arts (English Medium) इयत्ता ११ English Core
Question Bank Solutions for CBSE Arts (English Medium) इयत्ता ११ English Elective - NCERT
Question Bank Solutions for CBSE Arts (English Medium) इयत्ता ११ Entrepreneurship
Question Bank Solutions for CBSE Arts (English Medium) इयत्ता ११ Geography
Question Bank Solutions for CBSE Arts (English Medium) इयत्ता ११ Hindi (Core)
Question Bank Solutions for CBSE Arts (English Medium) इयत्ता ११ Hindi (Elective)
Question Bank Solutions for CBSE Arts (English Medium) इयत्ता ११ History
Question Bank Solutions for CBSE Arts (English Medium) इयत्ता ११ Mathematics
Question Bank Solutions for CBSE Arts (English Medium) इयत्ता ११ Political Science
Question Bank Solutions for CBSE Arts (English Medium) इयत्ता ११ Psychology
Question Bank Solutions for CBSE Arts (English Medium) इयत्ता ११ Sanskrit (Core)
Question Bank Solutions for CBSE Arts (English Medium) इयत्ता ११ Sanskrit (Elective)
Question Bank Solutions for CBSE Arts (English Medium) इयत्ता ११ Sociology
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×