Definitions [15]
When equal normal forces are applied on every surface of a body causing a change in volume, the restoring force opposing this change per unit area is called hydraulic stress (also called volume stress).
Strain is defined as the ratio of the change in dimensions of the body to its original dimensions.
OR
The ratio of change in configuration to the original configuration is called strain.
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It has no unit and no dimensions (pure ratio).
The ratio of change in length of the body to its initial length is called longitudinal strain: ε = ΔL/L.
The angular displacement of the surface in direct contact with the applied shear stress from its original position is called shear strain: τ = W/L = tan θ.
When there is an increase in the length or extension of the body in the direction of the applied force, the stress produced is called tensile stress.
When there is a decrease in the length or compression of the body due to the applied force, the stress produced is called compressive stress.
Answer in one sentence.
Define strain.
The strain is defined as the ratio of change in dimensions of the body to its original dimensions.
Strain = `"change in dimensions"/"original dimensions"`
The ratio of change in volume of the body to its original volume is called volume strain: ΔV/V.
The internal restoring force per unit area of a body is called stress.
OR
The internal restoring force acting per unit area of a deformed body is called stress.
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SI Unit: N/m² (pascal, Pa)
Dimensions: [M1L−1T−2]
The modulus of elasticity of a material is the ratio of stress to the corresponding strain. It is defined as the slope of the stress-strain curve in the elastic deforming region and depends on the nature of the material.
\[\frac {stress}{strain}\] = Constant
The constant is called the modulus of elasticity.
OR
The constant ratio of stress to strain within the elastic limit is called the Modulus of Elasticity.
The reciprocal of the bulk modulus is called compressibility: k = \[\frac {1}{B}\].
The point on the stress-strain curve up to which Hooke's Law is valid is called the proportional limit (Point A).
The stress at the yield point (end of elastic behavior and start of plastic deformation) is called the yield strength.
The maximum stress that a material can withstand is called the Ultimate Tensile Strength (Point D).
The point at which the material breaks and failure of the material takes place is called the fracture point (Point E).
Formulae [2]
- \[|\vec{F}|\] is the magnitude of the internal restoring force (which is equal to the external applied deforming force).
- A is the area over which the force acts.
- SI unit of stress: N m-2 or pascal (Pa).
- Dimensions of stress: [L-1M1T-2].
Theorems and Laws [1]
Hooke's Law was discovered by English scientist Robert Hooke in 1660. He first stated it as a Latin anagram: "As the extension, so the force."
Statement: For small deformations, stress is directly proportional to strain, within the elastic limit.
Key Points:
- Hooke's Law is a measure of elasticity.
- It is valid only up to the elastic limit. Beyond this, the material does not return to its original shape and Hooke's Law no longer applies.
- In springs: The force needed to extend or compress a spring by distance x is proportional to that distance → F = −kx (where k is the spring constant).
- Hooke's Law is applicable only in the case of elastic deformation.
Important Questions [13]
- Two Wires of the Same Material Have Radii Ra and Rb Respectively. the Radius of Wire a Is Twice the Radius of Wire B. If They Are Stretched by Same Load Then Stress on Wire B is
- The Compressibility of a Substance is the Reciprocal of _________
- State Hooke’S Law. Define Elastic Limit and Modulus of Elasticity.
- The Buckling of a Beam is Found to Be More If
- Find the Initial Mass, Assuming that Hooke'S Law is Obeyed
- Young’S Modulus of Material of Wire is ‘Y’ and Strain Energy per Unit Volume is ‘E’, Then the Strain is
- Stretching of a Rubber Band Results in
- Two springs of force constants K1 and K2 (K1> K2) are stretched by same force. If W1 and W2 be the work done stretching the springs then
- Within the Elastic Limit, Find the Work Done by a Stretching Force on a Wire.
- A Mass of 1 Kg is Hung from a Steel Wire If Radius 0.5 Mm and Length 4 M. Calculate the Extension Produced. What Should Be the Area of Cross-section of the Wire So that Elastic Limit is Not Exceeded? Change in Radius is Negligible
- The Ratio of Diameters of Two Wires of the Same Material and Length is N : 1. If the Same Load is Applied to Both the Wires Then Increases in the Length of the Thin Wire is
- A and B Are Two Steel Wires and the Radius of a is Twice that of B. If They Are Stretched by the Same Load, Then the Stress on B is
- The S.I. Unit of Compressibility is
