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प्रश्न
Two monochromatic beams, one red and the other blue, have the same intensity. In which case (i) the number of photons per unit area per second is larger, (ii) the maximum kinetic energy of the photoelectrons is more? Justify your answer.
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उत्तर
(i) Number of photons per unit per second in both the beams is same as they have the same intensity.
(ii) The maximum kinetic energy of photoelectrons is given by
E=hν−ϕw
hereh=Planck's constant
ν=Frequency of incident light
ϕ=Workfunction of the material
We know that the frequency of blue beam is more than that of red beam. So, from the equation of maximum kinetic energy, we can say that the maximum kinetic energy of the photoelectrons of the blue beam will be more
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संबंधित प्रश्न
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In an experiment of the photoelectric effect, the graph of maximum kinetic energy EK of the emitted photoelectrons versus the frequency v of the incident light is a straight line AB shown in Figure 6 below:

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2) The work function of the metal.
3) Stopping potential for the photoelectrons emitted by the light of frequency `v = 30 xx 10^14 Hz`
What change will you observe if intensity of incident radiation is changed but the frequency remains the same?
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With reference to the photoelectric effect, what is meant by threshold wavelength?
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