Question

While performing the experiment with raisins to determine the percentage of water absorbed by them, a student made following measurements:

Mass of water in the beaker = 40 g

Mass of raisins before soaking = 5 g

Mass of raisins after soaking for 2 hours = 8 g

Mass of water left in the beaker after the experiment = 35 g

The percentage of water absorbed by raisins is:

पर्याय

• `(40g-35g)/(35g)xx100`

• `(40g-35g)/(40g)xx100`

• `(8g-5g)/(8g)xx100`

• `(8g-5g)/(5g)xx100`

Answer 1

Not in Current Syllabus

The percentage of water absorbed by raisins is calculated by using the formula

`(W_2-W_1)/(W_1)xx100`

where, W₂ is the weight of wet resin and W₁ is the weight of dry resin.

The Correct Answer is D