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सी.आई.एस.सी.ई.आयसीएसई ICSE Class 7

Write Your Observation and Name the Product When Zinc Reacts with Dilute Hydrochloric Acid.

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प्रश्न

Write your observation and name the product when zinc reacts with dilute hydrochloric acid.

एका वाक्यात उत्तर
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उत्तर

When zinc pieces are added to hydrochloric acid, zinc displaces hydrogen. As a result, zinc chloride and hydrogen gas are produced.

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पाठ 5: Language of Chemistry - Additional questions

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एस.पी. सिंह Concise Chemistry [English] Class 7 ICSE
पाठ 5 Language of Chemistry
Additional questions | Q 9.1

संबंधित प्रश्‍न

State one characteristic of the chemical reaction which takes place when dilute sulphuric acid is added to barium chloride solution.


Write word equation for the following skeletal equation:

\[\ce{CO + O2 -> CO2}\]


Write the chemical equation for the following word equation and balance them.

Nitrogen + Oxygen → Nitrogen monoxide


Choose the correct answer from the options given below.

The formula of sodium carbonate is Na2CO3 and that of calcium hydrogen carbonate is


Write the balanced chemical equation of the following reaction. potassium bicarbonate + sulphuric acid → potassium sulphate + carbon dioxide + water


Match column A with column B. 

Column A Column B
(a) Blue salt changes to white and then black (i) Ammonium dichromate
(b) Orange coloured compound changes to green. (ii) Iodine
(c) Red compound changes to brown and then yellow. (iii) Zinc Nitrate
(d) White to yellow when hot and white when cold. (iv) Copper sulphate
(e) Violet solid changes to violet vapours. (v) Red Lead

An element X is trivalent. Write the balanced equation for the combustion of X in oxygen.


\[\ce{2KClO3->[MnO2] 2KCl + 3O2[g] - is a balanced equation.}\]

State what is a ‘balanced equation’.


Balance the following simple equation:

K  +   H2O   →   KOH   +   H2 


Which among the following is(are) double displacement reaction(s)?

  1. `"Pb" + "CuCl"_2 -> "PbCl"_2 + "Cu"`
  2. `"Na"_2"SO"_4 + "BaCl"_2 -> "BaSO"_4 + 2"NaCl"`
  3. `"C" + "O"_2 -> "CO"_2`
  4. `"CH"_4 + 2"O"_2 -> "CO"_2 + 2"H"_2"O"`

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